4.3 Article

Defining binary phylogenetic trees using parsimony: New bounds

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DISCRETE APPLIED MATHEMATICS
卷 341, 期 -, 页码 257-269

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DOI: 10.1016/j.dam.2023.08.005

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Maximum parsimony; Phylogenetic tree; Buneman theorem

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Phylogenetic trees are commonly used to model evolution. This manuscript presents new findings on the relationship between the maximum parsimony method and the definition of phylogenetic trees. The study shows that the set of characters with parsimony score k can uniquely define a binary phylogenetic tree T with n > 4k leaves. Additionally, the research expands this understanding to identify the range of n values for which trees sharing the same A(k)-alignment can exist. The study also highlights the relationship between the nearest neighbor interchange operation and the uniqueness of the A(k)-alignment.
Phylogenetic trees are frequently used to model evolution. Such trees are typically reconstructed from data like DNA, RNA, or protein alignments using methods based on criteria like maximum parsimony (amongst others). Maximum parsimony has been assumed to work well for data with only few state changes. Recently, some progress has been made to formally prove this assertion. For instance, it has been shown that each binary phylogenetic tree T with n >= 20k leaves is uniquely defined by the set A(k)(T), which consists of all characters with parsimony score k on T. In the present manuscript, we show that the statement indeed holds for all n > 4k, thus drastically lowering the lower bound for n from 20k to 4k. However, it has been known that for n <= 2k and k >= 3, it is not generally true that A(k)(T) defines T. We improve this result by showing that the latter statement can be extended from n <= 2k to n <= 2k + 2. So we drastically reduce the gap of values of n for which it is unknown if trees T on n taxa are defined by A(k)(T) from the previous interval of [2k + 1, 20k - 1] to the interval [2k + 3, 4k - 1]. Moreover, we close this gap completely for the nearest neighbor interchange (NNI) neighborhood of T in the following sense: We show that as long as n >= 2k + 3, no tree that is one NNI move away from T (and thus very similar to T) shares the same A(k)-alignment.

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