3.9 Article

Empirical Relationship Describing Total Convective and Radiative Heat Loss in Buildings

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INT INFORMATION & ENGINEERING TECHNOLOGY ASSOC
DOI: 10.18280/ijht.410201

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convective-radiative heat transfer infrared; camera experiments empirical equation; vertical plate

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Based on theoretical considerations of convective-radiative heat transfer, a relationship is developed to calculate the total convective and radiative heat flux emitted from any object at tw and its surroundings at t infinity. This relationship is then used to enhance the measurement capabilities of thermal imaging cameras, allowing them to measure temperature, heat losses, and other thermal properties of objects. Experimental validation confirms the accuracy and practicality of the proposed relationship.
On the basis of theoretical considerations of convective-radiative heat transfer, a relationship was developed enabling the total convective and radiative heat flux QC+R emitted from any object at tw and its surroundings at t infinity to be calculated from known values of the surface temperature of such an object, i.e., the known temperature difference Delta t=tw -t infinity and average air temperature Tav. This relationship is applied to thermal imaging cameras with the aim of developing appropriate software to enhance their measurement capabilities. They can then be used not only for monitoring and measuring temperature, local overheating, heat losses through insulation materials, thermal bridges, constructional defects, moisture, etc., but also for measuring the heat losses from any object, such walls and buildings. This empirical relationship includes constants relating to the object itself, such as its characteristic dimension l, surface area A, emissivity 6 and temperature parameters, which depend on tw, t infinity, Delta t and Tav and on the physical properties of air. Experimental validation of the proposed relationship, performed for two values of the surface emissivity 6, showing the discrepancies Delta QC+R=1.75% (for 6=0.884) and 4.85% (for 6=0.932), has confirmed its correctness and its practicability.

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