4.8 Article

Measurement of Compton Scattering from the Deuteron and an Improved Extraction of the Neutron Electromagnetic Polarizabilities

期刊

PHYSICAL REVIEW LETTERS
卷 113, 期 26, 页码 -

出版社

AMER PHYSICAL SOC
DOI: 10.1103/PhysRevLett.113.262506

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资金

  1. Swedish Research Council
  2. Knut and Alice Wallenberg Foundation
  3. Crafoord Foundation
  4. Swedish Institute
  5. Wenner-Gren Foundation
  6. Royal Swedish Academy of Sciences
  7. National Science Foundation [0855569]
  8. U.S. Department of Energy, Office of Science, Office of Nuclear Physics [DE-FG02-93ER40756, DE-FG02-95ER40907, DE-FG02-06ER41422]
  9. UK Science and Technology Facilities Council [ST/F012047/1, ST/J000159/1]
  10. Science and Technology Facilities Council [ST/J000159/1, ST/F012047/1, ST/J000175/1, ST/L005794/1] Funding Source: researchfish
  11. STFC [ST/L005794/1, ST/J000159/1, ST/J000175/1, ST/F012047/1] Funding Source: UKRI

向作者/读者索取更多资源

The electromagnetic polarizabilities of the nucleon are fundamental properties that describe its response to external electric and magnetic fields. They can be extracted from Compton-scattering data-and have been, with good accuracy, in the case of the proton. In contradistinction, information for the neutron requires the use of Compton scattering from nuclear targets. Here, we report a new measurement of elastic photon scattering from deuterium using quasimonoenergetic tagged photons at the MAX IV Laboratory in Lund, Sweden. These first new data in more than a decade effectively double the world data set. Their energy range overlaps with previous experiments and extends it by 20 MeV to higher energies. An analysis using chiral effective field theory with dynamical .Delta(1232) degrees of freedom shows the data are consistent with and within the world data set. After demonstrating that the fit is consistent with the Baldin sum rule, extracting values for the isoscalar nucleon polarizabilities, and combining them with a recent result for the proton, we obtain the neutron polarizabilities as an alpha(n) = [11.55 +/- 1.25(stat) +/- 0.2(BSR) +/- 0.8(th)] x 10(-4) fm(3) and beta(n) = [3.65 -/+ 1.25(stat) +/- 0.2(BSR) -/+ 0.8(th)] x 10(-4) fm(3), with chi(2) = 45.2 for 44 degrees of freedom.

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