Excited state deactivation pathways of neutral/protonated anisole and p-fluoroanisole: a theoretical study

The potential energy profiles of neutral and protonated anisole and p-fluoroanisole at different electronic states have been investigated extensively by the RI-MP2 and RI-CC2 methods. The calculations reveal that the relaxation dynamics in protonated anisole and p-fluoroanisole are essentially different from those of the neutral analogues. In neutral anisole/p-fluoroanisole, the (1)pi sigma* state plays a vital relaxation role along the O-CH3 coordinate, yielding the CH3 radical. For both of these molecules, the calculations indicate conical intersections (CIs) between the ground and excited state potential energy (PE) curves, hindered by a small barrier, and providing non-adiabatic gates for radiation-less deactivation to the ground state. Nevertheless, for the protonated cases, besides the prefulvenic deformation of the benzene ring, it has been predicted that the lowest (1)(sigma,n)pi* state along the C-O-C bond angle plays an important role in photochemistry and the relaxation dynamics. The S-1, S-0 PE profiles of protonated anisole along with the former reaction coordinate (out-of-plane deformation) show a barrierless relaxation pathway, which can be responsible for the ultrafast deactivation of excited systems to the ground state via the low-lying S-1/S-0 conical intersection. Moreover, the later reaction coordinate in protonated species (C-O-C angle from 120 degrees-180 degrees) is consequently accompanied with the bond cleavage of C-OCH3 at the (1)(sigma,n)pi* state, hindered by a barrier of similar to 0.51 eV, and can be responsible for the relaxation of excited systems with significant excess energy (h nu > 5 eV). Furthermore, according to the RI-CC2 calculated results, different effects on the S-1-S-0 electronic transition energy of anisole and p-fluoroanisole upon protonation have been predicted. The first electronic transitions of anisole and p-fluoroanisole shift by similar to 0.3 and 1.3 eV to the red respectively due to protonation.